Explain about Notations in Data Structures?

https://www.computersprofessor.com/2016/11/explain-about-notations-in-data.html
Evaluating expressions: let Q be an arithmetic expression
involving both operator &operands.
Operator: operator is a symbol that perform
a particular tasks.
High priority { 1 }, c, {-----
Next high priority *, /
Low priority + , -
Let Q = (5*6)+(2*10)+30*5+2
=
30+20+150+2
=202
Expressions are three types.
Expressions are also called notation.
1. Infix notation
2. Prefix notation
3. Postfix notation
1. Infix notation: operators are placed in between operands.
Ex: a+b
2. Prefix
notation : operators are placed before operands
Ex : +ab
3. Postfix
notation : operators are placed after operands.
Ex : ab+
Computers does not
understand infix and prefix notation It only understands postfix notation.
So that computer translates infix and prefix notations
into postfix notations then evaluate the post fix notations.
Evaluating Postfix Notation:
Algorithm:
Step – 1:let Q be an arithmetic expression writing in postfix notation.
Step – 2: Add right bracket at the end of the Q .scan Q from left to right and
repeat step 3 & step 4 until
the end of Q.
Step – 3: If an operand is encountered push it on to stack.
Step – 4: If an operator is encountered remove the top two elements and perform
res= a+b . and
place the result in top.
b= st[top--]
a=st[top--]
res =a + b.
and place the result in top
st[++top]=res
class Post
{
public static void main(String
args[ ])throws IOException
{
BufferedReader br=new BufferedReader(new
InputStreamReader (System.in());
int n;
System.out.println(“enter stack
size”);
n= Integer.parseInt(br.readLine(
));
int st[ ]=new int(n);
int a, b, res, ch;
do
{
System.out.println(“1:operator
2:operand \n”);
ch= Integer.parseInt (br.readLine());
switch(ch)
{
b=st[top - -];
a=st[top - -];
case 1:
System.out.println(“enter
operator”);
char x=br.readLine();
char op=x.charAt[0];
switch(op)
{
case ‘+’ :
res=a+b;
break;
case ‘-‘ :
res=a – b;
break
case ‘8’:
res = a *
b;
break;
case ‘%’:
r=a/b;
break;
}
st[++top]=res;
break;
case 3:
System.out.println(“enter
operand”);
st[++top]= Integer.parseInt (br.readLine());
break;
}
}while( ch < 3 ) ;
System.out.println(“res=”+res);
}
}