C# Questions & Answers on Continue, Goto Statements for Freshers

1. Select output for the following set of code :

1.   static void Main(string[] args)

2.   {

3.       int i;

4.       Console.WriteLine("enter value of i:");

5.       i = Convert.ToInt32(Console.ReadLine());

6.       if (i < 7)

7.       {

8.           i++;

9.           continue;

10.       }

11.       Console.WriteLine("final value of i:" +i);

12.       Console.ReadLine();

13.   }

a) 12
b) 11
c) Compile time error
d) 13

Answer: c

Explanation: ‘Continue’ loop cannot be used within ‘if’ loop .replace while with if(i <7 br="">Output: Compile time error.

2. Select the output for the following set of Code :

1.  static void Main(string[] args)

2.  {

3.      int i;

4.      Console.WriteLine("enter value of i:");

5.      i = Convert.ToInt32(Console.ReadLine());

6.      if ( i % 2 == 0)

7.          goto even:

8.      else

9.      {

10.          Console.WriteLine("number is odd:");

11.          Console.ReadLine();

12.      }

13.      even:

14.      Console.WriteLine("number is even:");

15.      Console.ReadLine();

16.  }

17. for i = 4.

a) number is odd
b) number is even
c) Compile time error
d) none of the mentioned

Answer: c

Explanation: “Undefined label ‘even’ in main().The syntax ‘goto even:’ is incorrect instead use ‘goto even;’.
Output:

1.     static void Main(string[] args)

2.     {

3.         int i;

4.         Console.WriteLine("enter value of i:");

5.         i = Convert.ToInt32(Console.ReadLine());

6.         if (i % 2 == 0)

7.         goto even;

8.         else

9.         {

10.             Console.WriteLine("number is odd:");

11.             Console.ReadLine();

12.         }

13.         even:

14.         Console.WriteLine("number is even:");

15.         Console.ReadLine();

16.     }

3. Select the output for the following set of code :

1.   static void Main(string[] args)

2.   {

3.       int i = 1, j;

4.       do

5.       {

6.           for (j = 1; ; j++)

7.           {

8.               if (j > 2)

9.                   break;

10.               if (i == j)

11.                   continue;

12.               Console.WriteLine(i + " " + j);

13.           }

14.           i++;

15.       } while (i < 3);

16.       Console.ReadLine();

17.   }

a) 1 2
2 1
b) 2 1
1 2
c) 1 3
2 1
d) 1 1
2 1

Answer: a

Explanation: for i = 1.When control enters in loop first if condition is checked for where j = 1 and as (j > 2) which is false.Control is now passed to console statement with i = 1 and j = 2.Now, in while condition value of ‘i’ reflected is 2 i.e i = 2 as i++.Since, (i < 3) control again enters in for loop with i = 2 but j = 1 not j = 2 for j++ and hence,again same condition executes for console statement.
Output : 1 2
2 1

4. Select the output for the following set of code :

1.    static void Main(string[] args)

2.    {

3.        int i = 10 , j = 0;

4.        label:

5.        i--;

6.        if ( i > 0)

7.        {

8.            Console.WriteLine(i+ " ");

9.            goto label;

10.        }

11.        Console.ReadLine();

12.    }

a) 1 2 3 4 5 6 7 8 9 10
b) 10 9 8 7 6 5 4 3 2 1 0
c) 9 8 7 6 5 4 3 2 1
d) 10 9 8 7 6 5 4 3 2 1

Answer: c

Explanation: for i = 10,loop executes for first time in ‘if’ loop as (i>0) i.e (9 > 0) and hence printing ‘9’.Similarly,label condition executes again go for (i–) i.e (9-1=8) and hence again prints i = 8.In this way looping condition executes as 9 ,8 to 3, 2, 1.
OUTPUT :9 8 7 6 5 4 3 2 1.

5. Select the output for the following set of code :

1.   static void Main(string[] args)

2.   {

3.       int i = 0, j = 0;

4.       while (i < 2)

5.       {

6.           l1: i--;

7.           while (j < 2)

8.           {

9.               Console.WriteLine("hi\n");

10.               goto l1;

11.           }

12.       }

13.       Console.ReadLine();

14.   }

a) hi hi hi
b) hi hi
c) hi
d) hi hi hi…..infinite times

Answer: d

Explanation: Since,i– so,test condition for ‘i’ never satisfies it fails and hence infinite loop in occurs.
output: hi hi hi…..

6. Select the output for the following set of code :

1.   static void Main(string[] args)

2.   {

3.       int i = 0;

4.       if (i == 0)

5.       {

6.           goto label;

7.       }

8.       label: Console.WriteLine("HI...");

9.       Console.ReadLine();

10.   }

a) Hi…infinite times
b) Code runs prints nothing
c) Hi Hi
d) Hi…

Answer: d

Explanation: for i = 0 ,if condition is satisfied as (i == 0).So,label statement is printed.
Output : Hi

7. Select the output for the following set of code :

1.   static void Main(string[] args)

2.   {

3.       int i = 0, j = 0;

4.       l1: while (i < 2)

5.       {  

6.           i++;

7.           while (j < 3)

8.           {

9.               Console.WriteLine("loop\n");

10.               goto l1;

11.           }

12.        }

13.       Console.ReadLine();

14.   }

a) loop is printed infinite times
b) loop
c) loop loop
d) Compile time error

Answer: c

Explanation: Since outer while loop i.e while(i<2 able="" and="" as="" be="" br="" breaks="" condition="" control="" could="" executes="" executing="" for="" goes="" i="2.hence,loop" j="" loop.="" loop="" not="" of="" only="" out="" satisfy="" third="" time="" times.hence="" to="" two="" while="">Output : loop loop.

8. Select output for the following set of code :

1.   static void Main(string[] args)

2.   {

3.       int i= 0,k;

4.       label: Console.WriteLine(i);

5.       if (i == 0)

6.           goto label;

7.       Console.ReadLine();

8.   }

a) 0 0 0 0
b) 0 0 0
c) 0 infinite times
d) 0

Answer: c

Explanation: Since, if condition is always true.Loop will continue executing always without any end condition.
Output:0 0 0….

9. Select the output for the following set of code :

1.    static void Main(string[] args)

2.    {

3.        int i = 0;

4.        int j = 0;

5.        for (i = 0; i < 4; i++)

6.        {

7.            for (j = 0; j < 3; j++)

8.            {

9.                if (i > 1)

10.                    continue;

11.                Console.WriteLine("Hi \n");

12.            }

13.        }

14.        Console.ReadLine();

15.    }

a) Prints hi 4 times
b) Prints hi 3 times
c) Prints hi 6 times
d) Prints hi infinite times

Answer: c

Output : hi
hi
hi
hi
hi
hi.

10. Select the output for the following set of code :

1.     static void Main(string[] args)

2.     {

3.         int a = 0;

4.         int i = 0;

5.         int b;

6.         for (i = 0; i < 5; i++)

7.         {

8.              a++;

9.              Console.WriteLine("Hello \n");

10.              continue;

11.         }

12.         Console.ReadLine();

13.     }

a) print hello 4 times
b) print hello 3 times
c) print hello 5 times
d) print hello infinite times

Answer: c

Explanation: Condition executes until and unless i < 5.So,it prints “hello” until ‘i’ condition is satisfied.
Output : Hello
Hello
Hello
Hello
Hello

11. Select the output for the set of code:

1.     static void Main(string[] args)

2.     {

3.         Console.WriteLine("HI");

4.         continue;

5.         Console.WriteLine("Hello");

6.         Console.ReadLine();

7.     }

a) Hi Hello
b) Hi
c) Hello
d) Compile time error

Answer: d

Explanation: Absence of any loop condition in order to make decision of break or continue.